If you know the intercepts.
Here is a sample problem:
Only the values of m and b are constant. So that's why you don't write what y and x are (in numbers) in the equation!
Here is a sample problem:
you have the intercepts:
x intercept: 4
y intercept: -2
1. From here, we can find out two points:
(4, 0) and (0, -2)
Now, since we have two points, we must have two equations.
y = mx + b is the standard equation of a line.
2. Let's plug the values in for the x intercept.
y = mx + b
0 = m (4) + b
0 = 4m + b
3. Now y intercept:
y = mx + b
-2 = m (0) + b
-2 = 0 + b
-2 = b
4. Since we found what b is in this equation, we can sub it into the first equation.
0 = m (4) + b, b = -2 * m (4) is the same as 4m.
0 = 4m -2
2 = 4m
2/4 = m
m = 2/4
m = 1/2
m = 0.5
5. Now we know what m and b are. We can form the equation of the line.
y = 0.5x -2
That is your answer!
Why can't you plug x and y intercept points into the same (ONE) equation? Because they change. They are not constant - x and y can be any number on the graph!
x intercept: 4
y intercept: -2
1. From here, we can find out two points:
(4, 0) and (0, -2)
Now, since we have two points, we must have two equations.
y = mx + b is the standard equation of a line.
2. Let's plug the values in for the x intercept.
y = mx + b
0 = m (4) + b
0 = 4m + b
3. Now y intercept:
y = mx + b
-2 = m (0) + b
-2 = 0 + b
-2 = b
4. Since we found what b is in this equation, we can sub it into the first equation.
0 = m (4) + b, b = -2 * m (4) is the same as 4m.
0 = 4m -2
2 = 4m
2/4 = m
m = 2/4
m = 1/2
m = 0.5
5. Now we know what m and b are. We can form the equation of the line.
y = 0.5x -2
That is your answer!
Why can't you plug x and y intercept points into the same (ONE) equation? Because they change. They are not constant - x and y can be any number on the graph!
Only the values of m and b are constant. So that's why you don't write what y and x are (in numbers) in the equation!
Also, if the question asks for you to put the equation in standard form, Ax + By = C, it is very simple!